Question

$\frac{5}{3} + \frac{4}{7} \div \frac{32}{21}$
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Answer 1

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$\frac{5}{3} + \frac{4}{7 } \div \frac{32}{21} \\ = > \frac{5}{3} + \frac{4}{7} \times \frac{21}{32} \\ = > \frac{5}{3} + \frac{3}{8} \\ = > \frac{40 + 9}{24} \\ = > \frac{49}{24} \\ = > 2 \frac{1}{24}$

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$2 \frac{1}{24}$

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BODMAS:-

B---Bracket

O---Of

D---Division

M---Multiplication

A---Addition

S---Subtraction.