Question

$\frac{6}{12} + \frac{ - 2}{4}$
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Answer 1

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$\frac{6}{12} + \frac{ - 2}{4} \\ \\ = \frac{6 - 6}{12} \\ \\ \frac{0}{12} \\ \\ = 0$

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Answer 2

$\sf \Large Solution!!$

$\sf \dfrac{6}{12}+\dfrac{-2}{4}$

Simplifying the fraction.

$\sf \dfrac{1}{2}+\dfrac{-1}{2}$

Taking the LCM.

$\sf \dfrac{1+(-1)}{2}$

$\sf \dfrac{1-1}{2}$

$\sf \dfrac{0}{2}\implies 0$

Since number is 0, then the fraction is 0