Question

$\frac{d}{dx} ( \frac{1}{2} \sec(x) \tan(x) + \frac{1}{2} ln( \sec(x) + \tan(x) )$
Hey anyone please answer the following Q​

Answer 1

Answer:

sec^3x

Step-by-step explanation:

= d/dx( 1/2 secx tanx + 1/2 ln(secx + tanx)

= 1/2 secx sec^2x + tanx secx tanx + 1/2

1/secx + tanx (secx tanx + sec^2x)

...(applying quotient and chain rule)

= 1/2 secx ( sec^2x + tan^2x) + 1/2 secx

= 1/2 secx ( sec^2x + sec^2x)

= sec^3x