Question

$\frac{ {sec}^{2} 60 - {tan}^{2} 60}{ {sin}^{2} 30 + {cos}^{2}30 }$

answer me please

Answer 1

Hello Friend....

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The answer of u r question is....

Ans:

Is in pic...

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Thank you...⭐️⭐️⭐️

Answer 2

Few Formulas,

• Sin²A + cos²A = 1
• sec²A - tan²A = 1


Hence,


[ sec²60 - tan²60 ] ÷ [ sin²30 + cos²30 ]

=> 1