Question

$\frac{x + 1} {4} + \frac{x + 2}{2} = \frac{x - 3}{2} - \frac{x - 1}{3}$
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Answer 1

Answer:

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Answer 2

Question

Solve the following:

$\rm\frac{x + 1} {4} + \frac{x + 2}{2} = \frac{x - 3}{2} - \frac{x - 1}{3}$

Answer

$\tt\frac{x \ + 1} {4} + \frac{x + 2}{2} = \frac{x - 3}{2} - \frac{x - 1}{3}$

$\implies \tt\frac{x \ + 1} {4} + \frac{x + 2}{2} = \frac{x - 3}{2} - \frac{x - 1}{3}$

By cross Multiplication,

$\small\tt \implies{2(x + 1) + 4(x + 2) = 3(x - 3) - 2(x - 1)}$

$\small\tt \implies{(2x + 1) + (4x + 8) = (3x - 9) - (2x + 2)}$

$\small\tt \implies{2x + 4x + (1 + 8) = 3x - 2x - ( - 9 + 2)}$

$\small\tt \implies{6x + 9 = x - 7}$

$\small\tt \implies{5x = ( - 2)}$

$\tt \implies{x = \frac{ - 2}{ \: \: 5}}$

The answer is $\large\frac{ - 2}{ \: \: 5}$