Question

Two kg of sugar and half kg of tea cost Rs 275 and three kg of sugar and one kg of tea cost Rs 500. Find the cost of two kg of sugar and two kg of tea.

Answer 1

hi mate,

Let the sugar be x

Let the tea be y:

First equation:

2x + 1/2 y = 275

Solve for y in this equaiton:

4x+y=550

y=550-4x (subsitution)

Second equation:

3x + 1y=500

Subsitute for y in this equation:

3x+(550-4x)=500

-x=500 -550

x=50

y=550-4(50)

y=350

for two kg.

x = 50×2=100

y = 350×2=700

Hence, the sugar costs RS. 100 and the tea costs RS.700 for two kg respectively.

i hope it helps you.

Answer 2

$\huge{\underline{\underline{Solution:-}}}$

Given that :-

$\sf\implies$ Let the sugar be x

$\sf\implies$ Let the tea be y

Then,

If,

$2x + \frac{1}{2}y = 275 ...........(i)eq. \\ \\ </p><p>\frac{4x + y}{2} = 275 \\ \\ </p><p>4x + y = 275 × 2 \\ \\ </p><p>4x + y = 550 \\ \\ </p><p>y = 550 - 4x$

y = 550 - 4x ..........(ii)eq.

Then, in second case;

3x + y = 500 .........(iii)eq.

Find out,

2x = sugar

2y = tea

Then according to questions;

now putting the value of y on (iii)eq.

3x + y = 500

3x + 550 - 4x = 500

3x - 4x = 500 - 550

-x = -50

x = 50

$\huge{\boxed{\red{x = 50} }}$

Now again ,

Putting the value of x on (iii)eq.

3x + y = 500

3 × 50 + y = 500

150 + y = 500

y = 500 - 150

y = 350

$\huge{\boxed{\red{y = 350} }}$

Therefore,

2x + 2y = ?

= 2 × 50 + 2 × 350

= 100 + 700

= 800

Thus, the answer will be

$\huge{\boxed{\red{ 2x + 2y = 800} }}$