Question

$\frac{x + 2}{3} - \frac{x - 3}{4} = 5 - \frac{x - 1}{2}$
THIS IS FROM LENIER EQATIONS FROM ONE VARIABLE


GIVE CORRECT ANS PLEASE​

Answer 1

Answer:

$\red { Value \:of \:x } \green {= 7 }$

Step-by-step explanation:

$\frac{x + 2}{3} - \frac{x - 3}{4} = 5 - \frac{x - 1}{2}$

$\implies \frac{x + 2}{3} - \frac{x - 3}{4} + \frac{x - 1}{2} = 5$

$\implies \frac{ 4(x+2) - 3(x-3) + 6(x-1) }{12} = 5$

$\implies 4x+8-3x+9+6x-6 = 60$

$\implies 7x +11 = 60$

$\implies 7x = 60 - 11$

$\implies 7x = 49$

$\implies x = \frac{49}{7} = 7$

Therefore.,

$\red { Value \:of \:x } \green {= 7 }$

••♪♪

Answer 2

Answer:

x=7

Step-by-step explanation:

multiply all terms by 12

$12 \times \frac{x + 2}{3} - 12 \times \frac{x - 3}{4} = 12 \times 5 - 12 \times \frac{x - 1}{2}$

now divide according to tables

then we will get

$4(x + 2) - 3(x - 3) = 60 - 6(x - 1)$

then multiply

$4x + 8 - 3x + 9 = 60 - 6x + 6$

now solve

$x + 17 = 66 - 6x$

$x + 6x = 66 - 17$

$7x = 49$

$x = \frac{49}{7}$

therefore,

$x = 7$

hope it helps