Question

$\frac{ {x}^{2} - 7x + 12}{x - 3} = 0$
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Answer 1

Step-by-step explanation:

$</p><p>\frac{ {x}^{2} - 7x + 12}{x - 3} = 0$

$</p><p>\frac{ {x}^{2} - \: 3x \: - \: 4x \: + 12}{x - 3} = 0$

$\frac{x(x - 3) \: - 4(x - 3)}{(x - 3)} = 0$

$\frac{(x - 4)(x - 3)}{(x - 3)}$ =0

x - 4 = 0

x = 4

hope it's helpful mark as brainliest.