Question

$\frac{x+4}{4} -\frac{2x-3}{2} = \frac{x}{8}$

Answer 1

$\dfrac{x + 4}{4} - \dfrac{2x - 3}{2} = \dfrac{x}{8} \\ \\ \dfrac{1 \times (x + 4) - 2 \times (2x - 3)}{4} = \dfrac{x}{8} \\ \\ \dfrac{x + 4 - 4x + 6}{4} = \dfrac{x}{8} \\ \\ 8 \times ( - 3x + 10) = 4 \times x \\ \\ - 24x + 80 = 4x \\ \\ - 28x = - 80 \\ \\ x = \dfrac{80}{28} \\ \\ x = \frac{20}{7}$

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