Question

$\frac{ {x}^{p} }{ {x}^{p} + {x}^{q} } + \frac{1}{ {x}^{p - q} }$
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Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\\frac{x^p}{x^p+x^q} + \frac{1}{x^{p-q}}\\\\\ Solution:\\\\\frac{x^p}{x^p+x^q} + \frac{1}{x^{p-q}}\\\\\rightarrow \frac{x^p}{x^{p}+x^{q}} + \frac{1}{x^{p-q}}\\\\\rightarrow \frac{x^p(x^{p-q})+{x^{p}+x^{q}}}{({x^{p}+x^{q}})(x^{p-q})} \\\\\rightarrow \frac{x^p((x^{p-q})+x^{q})}{({x^{p}+x^{q}})(x^{p-q})} \\\\\rightarrow \frac{x^p(x^{p}x^{-q}+x^{q})}{({x^{p}+x^{q}})(x^{p-q})}$

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