Question

$\frac{y - (4 - 3y)}{2y - (3 + 4y)} = \frac{1}{5}$
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Answer 1

Answer:

$\frac{y - (4 - 3y)}{2y - (3 + 4y)} = \frac{1}{5} \\ \frac{y - 4 + 3y}{2y - 3 - 4y} = \frac{1}{5} \\ \frac{4y - 4}{ - 2y - 3} = \frac{1}{5} \\ 5(4y - 4) = 1( - 2y - 3) \\ 20y - 20 = - 2y - 3 \\ 20y + 2y = - 3 + 20 \\ 22y = 17 \\ \boxed{ \large y = \underline{ \underline{ \frac{17}{22} }}}$