Question

$Hello \ answer \ this \ question \ please \\\\1 ) 2xy + 3x^{2}y + 3x^{2}y + 4xy , -12xy \\\\\\2 ) 2x^{2} + 3xy + 3y^{2} , 4x^{2} + 6xy + 13xy^{2} + 14x^{2}+ 2xy +2 y^{2}$

Answer 1

Step-by-step explanation:

$1)2xy + 3 {x}^{2} y + 3 {x}^{2} y + 4xy - 12xy \\ = 2xy + 4xy - 12xy + 3 {x}^{2} y + 3 { x}^{2} y \\ = - 6xy + 6 {x}^{2} y$

Hope, it helpful for you

Answer 2

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$1) \: 2xy + 3x^{2}y + 3x^{2}y +4xy ,-12xy$

$(2xy \: + \: 4xy \: + \: 12xy \\ \: + \: (3x^{2}y + 3x^{2}y ) \\ = - 6xy + 6 {x}^{2}y$

$2 ) 2x^{2} + 3xy + 3y^{2} , 4x^{2} + 6xy + 13xy^{2} + 14x^{2}+ 2xy +2 y^{2}$

$(3xy + 6xy + 2xy) \\ + (2 {x}^{2} + 4 {x}^{2} + 14 {x}^{2} \\ + (2 {y}^{2} + 3 {y}^{2} + 13 {y}^{2} \\ = 11xy + 20 {x}^{2} + 18 {y}^{2}$

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