Question

$\huge\bf\purple {Question}$






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If D and E are points on the sides AB and AC respectively of △ ABC such that AB = 5.6 cm , AD = 1.4 cm , AC = 7.2 cm and AE = 1.8cm , show that
DE || BC.



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Answer 1

$\large\bf\red{Answer:-}$

Hey There,

We have, DE || BC We have,

AB = 5.6 cm,

AD = 1.4 cm,

AC = 7.2 cm

AE = 1.8 cm

∴ DB = AB – AD

= 5.6 – 1.4

⇒DB = 4.2 cm.

_____________________

∴ EC = AC – AE

= 7.2 – 1.8

⇒EC = 5.4 cm

Thus, DE divides sides AB and AC of ΔABC in the same ratio. Therefore, by the converse of basic proportionality theorem.

• See The Attachment For your Structure Of Diagram.

Know More :-

★ Converse of Basic Proportionality Theorem :-

If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side. If a line passing through one vertex of a triangle divides the base in the ratio of the other two sides, then it bisects the angle.

Answer 2

Answer:

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