Find the wavelength of the 5th line of Balmer series
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Solution :-
- 1/λ = RZ2[ 1/n12 - 1/n22 ]
- N1 = 2
- N2 = 7
- R = 1.1×107
- 1/λ = 1.1×107[ 1/4 - 1/49 ]
- Λ = 396nm
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