Question

$\huge\blue{Question}$
(32)
If cos 8 teta = sin teta and 9 teta < 90°, then what is the value of tan 6 teta ?

▪︎from Trigonometry - grade 10
▪︎Step by step answer is required ​

Answer 1

Step-by-step explanation:

Answer:

\sqrt{3}.

3

.

Step-by-step explanation:

As given in the question,

cos8\theta\ =\ sin\thetacos8θ = sinθ

= > \ sin(90-8\theta)\ =\ sin\theta=> sin(90−8θ) = sinθ

= > \ 90-8\theta\ =\ \theta=> 90−8θ = θ

= > \ 9\theta\ =\ 90=> 9θ = 90

= > \ \theta\ =\ 10=> θ = 10

Now, we have to find the value of

tan6\thetatan6θ

=\ tan(6\times 10)= tan(6×10)

=\ tan(60)= tan(60)

=\ \sqrt{3}=

3

Hence, the value of tan6\thetatan6θ will be \sqrt{3}.

3

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Answer 2

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