Question

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A family of 12 buys 30 kg of sugar which lasts for 20 days. If they buy 40 kg and it lasts for only 8 days, find the increase in the number of family
members.

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Answer 1

Answer:

$\huge \bold \red{Question}$

A family of 12 buys 30 kg of sugar which lasts for 20 days. If they buy 40 kg and it lasts for only 8 days, find the increase in the number of family

members.

Solution :

In First Case:

A family of 12 Menbers buys 30 kg of sugar which lasts for 20 days. (given)

ATQ: Men : 12

Time : 20days

Work done according to question : 30

In Second Case:

A family of ? members buys 40 kg of sugar which lasts for 8 days

ATQ: Men : x

Time : 8 days

Work done according to question : 40

According to Maths Formula

$= \frac{men \times time}{work} \\ \frac{12 \times 20}{30} = \frac{x \times 8}{40} \\ \frac{4 \times 2 \times 40}{8 } = x \\ 40 = x \\ x = 40$

In First Case, family members = 12

In Second Case, family members = 48

Therefore, Increase in the number of family members in Second Case is 28(40-12).

Answer 2

Question:

A family of 12 buys 30 kg of sugar which lasts for 20 days. If they buy 40 kg and it lasts for only 8 days, find the increase in the number of family members.

Solution :

In First Case:

A family of 12 Menbers buys 30 kg of sugar which lasts for 20 days. (given)

ATQ: Men : 12

Time : 20days

Work done according to question : 30

In Second Case:

A family of ? members buys 40 kg of sugar which lasts for 8 days

ATQ: Men : x

Time : 8 days

Work done according to question : 40

According to Maths Formula

$= \frac{men \times time}{work \: done} \\ \frac{12 \times 20}{30} = \frac{x \times 8}{40} \\ \frac{12 \times 20 \times 40}{30 \times 8} = x \\ 40 = x \\ x = 40$

In First Case, family members = 12

Second Case, family members = 40

Therefore, Increase in the number of family members in Second Case is 28(40-12).