Question

$\huge\bold\red{Question}$

→ An armored car 2m long and 3m wide is moving at 10m/s when a bullet hits it in a direction making an angle tan^-3/4 with the length of the car as seen by a stationary observer.The bullet enters one edge of the car at corner and passes out at the diagonally opposite corner.Neglecting any interaction between the car and the bullet and effect of gravity,the time for the bullet to cross the car is ?
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Answer 1

Answer:

$x-component =vcosθ−10 (Considering relative velocity of the bullet w.r.t. car.)</p><p>y-component vsinθ</p><p>⇒vsinθ⋅t=3</p><p>⇒(vcosθ−10)t=2</p><p>⇒v⋅53⋅t=3⇒v=t5</p><p>⇒(t5⋅54−10)t=2</p><p>⇒4−10t=2</p><p>⇒2=10t</p><p></p><p>$

Explanation:

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