Question

$\huge\bold\red{QUESTION}$
Calculate the mass of non-volatile solute (molar mass 40g mof which should be disse
114r Octane to reduce its vapour pressure to 80%.

​$\huge\bold\green{THANKS}$​

Answer 1

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Ps = 80% of P0=0.80

Solute = W40g mol−1

Solvent (octane) = 114g 114gmol−1

(molar mass of C8H18=114gmol−1)

Now P0−PsP0=x2

∴P0−0.80P0P0=W40W40+1

Or 0.8W40=0.2

⇒W=10g

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Answer 2

Answer -

• The mass of a non-volatile solute of molar mass 40 g /mol that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is 10 g.Let w g of the non-volatile solute is used. Its molar mass is 40 g/mol.

Refer the attachment For Calculations →

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