Question

$\huge\bold\red{Question:-}$

Subtract the sum of 13x-4y+72 and -6z+6x+3y from the sum of 6x-4y-4z and 2x+4y-7.​

Answer 1

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$\large\mathsf\red{Sum \ of \ first \ 2 \ terms \ -}$

$\mathsf{(13x - 4y + 72) + (-6z + 6x + 3y)}$

$\large\mathsf\green{Open \ the \ Brackets}$

$\mathsf{= \ 13x - 4y + 72 - 6z + 6x + 3y}$

$\large\mathsf\green{Combine \ like \ terms}$

$\mathsf{= \ 13x + 6x - 4y + 3y + 72 - 6z}$

$\mathsf{= \ 19x - y - 6z + 72}$ ______________(1)

$\large\mathsf\red{Sum \ of \ second \ 2 \ terms \ -}$

$\mathsf{(6x - 4y - 4z) + (2x + 4y - 7)}$

$\large\mathsf\green{Open \ the \ Brackets}$

$\mathsf{= \ 6x - 4y - 4z + 2x + 4y - 7}$

$\large\mathsf\green{Combine \ like \ terms}$

$\mathsf{= \ 6x + 2x - 4y + 4y - 7 - 4z}$

$\mathsf{= \ 8x - 4z - 7}$ __________________(2)

$\mathsf{Now,}$

$\mathsf\pink{Subtract \ (1) \ from \ (2)}$

$\mathsf{(8x - 4z - 7) - (19x - y - 6z + 72)}$

$\large\mathsf\green{Open \ the \ Brackets}$

$\mathsf{= \ 8x - 4z - 7 - 19x + y + 6z - 72}$

$\large\mathsf\green{Combine \ like \ terms}$

$\mathsf{= \ 8x - 19x - 4z + 6z - 7 - 72 + y}$

$\large\textbf\blue{= \ -11x + 2z - 79 + y}$

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Answer 2

$\huge\bold\orange{Answer:-}$

First of all Find sum

$\sf\red{sum of 13x-4y+72 and -6z+6x+3y}$

13x -4y + 72 -6z + 6x + 3y = 19x -y -6z + 72

Sum of 13x-4y+72 and -6z+6x+3y. is 19x -y-6z+72_________1

$\sf\red{sum of 6x -4y-4z and 2x +4y-7}$

6x -4y -4z +2x +4y -7 = 8x -4z-7

Sum of 6x -4y-4z and 2x+4y-7 is 8x-4z-7_______2

Now ,

Subtract 19x-y-6z+72 from 8x-4z-7

8x-4z-7-(19x-y-6z+72)

8x-4z-7-19x+y+6z-72

$\sf\pink{-11x+2z+y-79}$ is the final answer