Question

$\huge\boxed{\bigstar \mathsf{Question} \bigstar }$

∆ABC is a right angle triangle, right angled at B. BD perpendicular to AC. what is AC×DC?

✅ Quality answer required
❌wrong answer = 20 answers reported​

Answer 1

Answer:

BD/CD=AD/BD

BD/CD=AD/BDBD^2=AD×DC

Step-by-step explanation:

In triangle BDA

→let angle DBA=x°,by angle sum property of triangle angle BAD=90-x°

In triangle CDB

→angle DBC=90-x°,by angle sum property of triangle angle DCB=x°

therefore,

triangle BDA is similar to triangle DBC

So,

BD/CD=AD/BD

BD²=AD*DC

hope it's helpful to you!