Math, asked by nikitagarg9, 1 year ago


\huge\boxed{hlo}

please solve the attachment ASAP !!!

Attachments:

aryandhar7450: Hey cutipie please reply
nikitagarg9: hii
aryandhar7450: How are you
aryandhar7450: Hey cutipie can we talk on Inbox
aryandhar7450: Hi cutipie good morning please think about it
aryandhar7450: Hey afreen why did you leave the inbox
aryandhar7450: Hi good morning afreen please reply back
aryandhar7450: Hey afreen please reply back yarr
aryandhar7450: Afreen please reply back yarr

Answers

Answered by aryandhar7450
1

Answer is 0


Step-by-step explanation is givenbelow in the photo


Attachments:

aryandhar7450: Please reply cutipie
aryandhar7450: Hey cutipie why are you ignoring me
nikitagarg9: no i am not ingorung
nikitagarg9: ingorning
aryandhar7450: Ok sorry for that
aryandhar7450: Hey cutipie can we chat on Inbox
aryandhar7450: Hi cutipie good morning please think about it
aryandhar7450: Hi cutipie
aryandhar7450: Hey afreen why did you leave the inbox
aryandhar7450: hi good morning afreen and why did you leave the inbox
Answered by boffeemadrid
2

Answer:


Step-by-step explanation:

The given equation is:

T_{n}=sin^{n}{\theta}+cos^{n}{\theta}

Now, T_{10}=sin^{10}{\theta}+cos^{10}{\theta}

=(sin^{5}{\theta})^{2}+(cos^{5}{\theta})^{2}=1

Also, T_{8}=sin^{8}{\theta}+cos^{8}{\theta}

=(sin^{4}{\theta})^{2}+(cos^{4}{\theta})^{2}=1

and, T_{6}=sin^{6}{\theta}+cos^{6}{\theta}

=(sin^{3}{\theta})^{2}+(cos^{3}{\theta})^{2}=1

Thus, the given equation becomes:

6T_{10}-15T_{8}+10T_{6}-1=6(1)-15(1)+10(1)-1=6-15+10-1=-9+9=0.

Similar questions