Which term of an Ap -557,-553,-549 will be the first positive term
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a (first term) = -57
d(common difference) = second term - first term
= -553-(-557)
=-553+557
= 4
Let nth term be the first positive term of the AP.
For Any term to be positive, it should be greater than 0 .
So, an>0 .
Then,
an>0= a+(n-1)d >0
= {-557 +(n-1) × 4 }>0
={-557 +4n-4} >0
={-561+4n}>0
= -561 > - 4n
=561 > 4n
= 561/4 >n
= 140.25 > n
So, n>140 .25 ,
so, n=141 .
Therefore 1st positive term will be 141th term.
d(common difference) = second term - first term
= -553-(-557)
=-553+557
= 4
Let nth term be the first positive term of the AP.
For Any term to be positive, it should be greater than 0 .
So, an>0 .
Then,
an>0= a+(n-1)d >0
= {-557 +(n-1) × 4 }>0
={-557 +4n-4} >0
={-561+4n}>0
= -561 > - 4n
=561 > 4n
= 561/4 >n
= 140.25 > n
So, n>140 .25 ,
so, n=141 .
Therefore 1st positive term will be 141th term.
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