Question

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solve this question

Ques 12​

Answer 1

Step-by-step explanation:

(i)

Here, we have

∠CRQ = ∠CBA = 90°

Thus, RQ ∣∣​ AB

Now, In ∆ABC,

Q is the mid-point of AC and QR ∣∣​ AB​.

Thus, R is the mid-point of BC.

In the same way, P is the midpoint of DC.

Hence,

DP = PC

(ii)

Now, In ∆​CDB,

P and R are the mid points of DC and BC respectively.

Since, AC = BD

Then, by mid-point theorem, we get:

PR = 1/2 BD

Now, diagonals of a rectangle are equal.

Therefore putting BD = AC, we get

PR = 1/2 AC

Hope it helps!

Answer 2

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