Question

$\huge{ \boxed{ \purple{\tt{ǫᴜᴇsᴛɪᴏɴ}}}}$
$\sf{prove \: by \: simplifying \:only \: one \: side : }$
$\sf{sin {}^{2} \theta + cos {}^{2} \theta = sec {}^{2} \theta - tan {}^{2} \theta}$
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Answer 1

Answer:

using identity

$\sin^{2}theta + \cos^{2}theta = 1$

$\sec^{2} theta - \tan^{2} theta \: = 1$

Step-by-step explanation:

therefore 1=1

LHS=RHS