Question

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Answer 1

$\huge\boxed{\underline{\mathcal{\red{A}\green{n}\pink{s}\orange{w}\blue{e}\red{r}}}}$

Refer To the attachment Dear...

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Answer 2

We have 

(x+1)2+1=0(x+1)2+1=0 

⇒(x+1)2−(i)2=0⇒(x+1)2−(i)2=0

⇒(x+1+i)(x+1−i)=0⇒(x+1+i)(x+1−i)=0 

∴x=−(1+i)−(1−i)∴x=−(1+i)−(1−i) 

α15+β15=(α2)7α+(β2)7βα15+β15=(α2)7α+(β2)7β 

= -128 (-i + 1 + i + 1) 

= - 256