Question

$\huge\boxed{\underline{\sf{\red{Qu}\green{e}\purple{st}\orange{i}\blue{o}\pink{n:-}}}}$

solve the question given in the attachment. ​

Answer 1

$\huge\boxed{\underline{\mathfrak{\red{A}\green{n}\purple{s}\orange{w}\blue{e}\pink{r:-}}}}$

REFER THE IMAGE..HOPE THIS HELPS YOU ☺️☺️❣️❤️

Answer 2

Answєr :-

x = 1 ís thє root gívєn !

Vαluє of ' k '

x² + kx + 3 = 0

( 1 )² + k ( 1 ) + 3 = 0

1 + k + 3 = 0

k = 0 - 4

k = - 4

Vαluє of ' x '

x² + kx + 3 = 0

x² + ( -4 ) x + 3 = 0

x² - 4x + 3

x [ x - 1 ] - 3 [ x - 1 ]

∴ x = 1 ( Gívєn ín thє quєstíon )

x - 3 = 0

x = 3

Hᴏᴘᴇ Tʜɪs Hᴇʟᴘs Yᴏᴜ