Question

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ABCD in which AB= 6 cm, CD=5 cm, DA -3.5 cm, C= 120° and D= 75????
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Answer 1

Explanation:

Refer to the above attachment

By applying heron's formula in triangle ABC having the sides 7 cm,6 cm and 9 cm, we have

s=

2

7+6+9

=11 cm

Area of triangle =

s(s−a)(s−b)(s−c)

=

11(11−7)(11−6)(11−9)

=

440

cm

2

Now, in triangle ADC having sides 15 cm,12 cm and 9 cm, we have

s=

2

15+12+9

=18 cm

=

18(18−15)(18−12)(18−9)

=54 cm

2

There, the area of quadrilateral ABCD=(

440

+54) cm

2

Can we be frnds??

Answer 2

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