Question

$\huge\color{pink}\mathfrak{Help Needed}$

$\bold\color{red}{Prove\:that\:\frac{secA} {tanA+cotA} =sinA}$


PLZ ANSWER ASAP

PLZ PLZ PLZ​

Answer 1

$\sf\underline{Answer:}$

Refer to the attachment

Have a good day!

Answer 2

How can I prove that

$\tt sinA tanA + cosA = secA?$

Let’s see. We can start by writing it out, and then manipulating each side to make them equal.

$\tt ⟹ sinA∗tanA+cosA=secA$

I usually convert things to sin and cos just to make it more familiar.

$\tt →sinA∗sinAcosA+cosA=1cosA$

Now you can reduce the fraction on the left.

$\tt ⟹ sin2AcosA+cosA=1cosA$

Now you can manipulate cosA to get a common denominator

And voila!ㅤㅤ

$\tt \large\mathbb\blue{HOPE\:IT\:HELPS}$