Question

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A cylindrical pillers has a diameter of 56 cm and is of 35 m high there are 16 pillers around the building find the cost of painting the curved surface area of all the pillars at the rate of 5.50 per 1m square ?​

Answer 1

Answer:

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A cylindrical pillers has a diameter of 56 cm and is of 35 m high there are 16 pillers around the building find the cost of painting the curved surface area of all the pillars at the rate of 5.50 per 1m square ?

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Radius=

$\frac{ \sf{diameter}}{2} \\ \\ = \frac{ \cancel{56} \: \: ^{28} }{ \cancel2} \\ \\ = 28cm$

$\frac{28}{100} m = 0.28m$

Height of cylindrical pillar=35 cm

curved area of cylindrical pillar =

$2\pi rh \\ \\ = 2 \times \frac{22}{7} \times 0.28 \times 35 \\ \\ = {61.6m}^{2}$

Curved area of 16 pillars =

$16 \times 61.6 = {985.6m}^{2}$

Cost of 1m^2 painting = Rs 5.50

cost of 985.6m^2

=

$985.6 \times 5.50 \\ \\ = \blue{5420.8}$

So Rs 5420.8 is answer

Hope it helps you from my side

Answer 2

The diameter of the cylindrical pillars is 56 cm, which means the radius is 28 cm or 0.28 m. The height of the pillars is 35 m.

The curved surface area of each pillar can be calculated using the formula:

$CSA = 2\pi rh$

where $\pi$ is the mathematical constant pi (approximately 3.14), $r$ is the radius of the pillar, and $h$ is the height of the pillar.

Substituting the values we get:

$CSA = 2 \times 3.14 \times 0.28 \times 35 = 78.12$ square meters

The total curved surface area of all 16 pillars is:

$Total CSA = 16 \times CSA = 16 \times 78.12 = 1250$ square meters

Now, we can calculate the cost of painting the curved surface area at the rate of 5.50 per 1 square meter:

$Cost = Total CSA \times 5.50 = 1250 \times 5.50 = 6875$ rupees

Therefore, the cost of painting the curved surface area of all the pillars at the rate of 5.50 per 1 square meter is 6875 rupees.