Question

$\huge\fbox\colorbox{yellow}{Question}$

a large truch and a car both moving with a velocity V , have a head on collision and both of them come to a half after that.if the collision lasts for 1 s :
(a) which vehicle experiences the greater force of impact ?
(b) which vehicle experiences the greater force change in momentum?
(c) which vehicle experiences the greater acceleration?
(d)why is the car likely to suffer more damage than the truck?



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Answer 1

Answer:

Initial velocity ,u = 0m/s

Distance covered ,s = 15m

Time taken ,t = 3 s

To Find:-

Distance covered by it in 12 second.

Solution:-

It is given that the body starts from rest and moving with a constant acceleration . We have to calculate the distance covered by it in 12 second . Firstly we calculate the acceleration of the body . Using 2nd equation of motion

s = ut + 1/2at²

where,

s denote distance covered

u denote initial velocity

t denote time taken

a denote acceleration

Substitute the value we get

:\implies:⟹ 15 = 0×3 + 1/2×a × 3²

:\implies:⟹ 15 = 0 + 1/2 × a × 9

:\implies:⟹ 15×2 = 9 × a

:\implies:⟹ 30 = 9× a

:\implies:⟹ a = 30/9

:\implies:⟹ a = 10/3 m/s² = 3.33 m/s²

Now, calculating the distance covered by body in 12 second . Again using 2nd equation of motion

s = ut + 1/2 at²

substitute the value we get

:\implies:⟹ s = 0 × 12 + 1/2 × 10/3 × 12²

:\implies:⟹ s = 0 + 5/3 × 144

:\implies:⟹ s = 5 × 48

:\implies:⟹ s = 240 m

Hence the distance covered by the body in 12 second is 240 metres.

Explanation:

Initial velocity ,u = 0m/s

Distance covered ,s = 15m

Time taken ,t = 3 s

To Find:-

Distance covered by it in 12 second.

Solution:-

It is given that the body starts from rest and moving with a constant acceleration . We have to calculate the distance covered by it in 12 second . Firstly we calculate the acceleration of the body . Using 2nd equation of motion

s = ut + 1/2at²

where,

s denote distance covered

u denote initial velocity

t denote time taken

a denote acceleration

Substitute the value we get

:\implies:⟹ 15 = 0×3 + 1/2×a × 3²

:\implies:⟹ 15 = 0 + 1/2 × a × 9

:\implies:⟹ 15×2 = 9 × a

:\implies:⟹ 30 = 9× a

:\implies:⟹ a = 30/9

:\implies:⟹ a = 10/3 m/s² = 3.33 m/s²

Now, calculating the distance covered by body in 12 second . Again using 2nd equation of motion

s = ut + 1/2 at²

substitute the value we get

:\implies:⟹ s = 0 × 12 + 1/2 × 10/3 × 12²

:\implies:⟹ s = 0 + 5/3 × 144

:\implies:⟹ s = 5 × 48

:\implies:⟹ s = 240 m

Hence the distance covered by the body in 12 second is 240 metres.

Answer 2

$\huge\fbox\colorbox{violet}{Question}$

a large truck and a car both moving with a velocity V , have a head on collision and both of them come to a half after that.if the collision lasts for 1 s :

1. which vehicle experiences the greater force of impact ?
2. which vehicle experiences the greater force change in momentum?
3. which vehicle experiences the greater acceleration?
4. why is the car likely to suffer more damage than the truck?

$\huge\fbox\colorbox{violet}{Answer}$

1. As the action (force) and the reaction (force) are equal and opposite, both the vehicles experience the same force on collision.
2. Since the change in momentum of truck is equal and opposite to the change in momentum of car, both of vehicles experience equal change in momentum.
3. As the force on each vehicle is the same but the mass of car is smaller than the truck therefore the car is smaller than the truck, therefore, the car experiences the greater acceleration (or greater retardation)
4. $because \: a = \frac{f}{m}$
5. Since the car is much lighter than the truck, therefore, the car is likely to suffer more damage during the collision than the truck (the car has greater retardation than the truck).