Question

The sides of a triangle are in the ratio 3:5:7 and its perimeter is 45 cm. What are the

lengths of the sides ?

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Answer 1

Answer:

$\huge \boxed{ \bold{ \underline{ \mathfrak{ \green{ \: \:answer}}}}}$

Step-by-step explanation:

Given :-

The sides of a triangle are in the ratio 3:5:7 and its perimeter is 45 cm. What are the lengths of the sides ?

To find :-

Lengths of sides .

Solution :-

$\big \bold{ratio \: of \: sides} \: \rightarrow \: \fbox{3:5:7}$

$\big \bold{their \: perimeter} \rightarrow \: \big \boxed{45 \: cm}$

$3x \: + \: 5x \: + \: 7x = \boxed{45 \: cm}$

$15x = \boxed{45 \: cm}$

$x = 45 \div 15$

$x = 3$

Then length of sides are →

$\huge a) \large 3x = 3 \times 3 = \boxed{9 \: cm}$

$\huge \: b) \large 5x = 5 \times 3 = \boxed{15 \: cm}$

$\huge \: c) \large \: 7x = 7 \times 3 = \boxed{21 \: cm}$

Answer 2

Answer:

9,15,21

Step-by-step explanation:

$3 x + 5x + 7x = 45 \\ 15x = 45 \\ x = 45 \div 15 \\ x = 3 \\ 3x = 3 \times 3 = 9 \\ 5x = 5 \times 3 = 15 \\ 7x = 7 \times 3 = 21$