Question

$\huge \fbox \green{Question}$
In an electric circuit two resistors R1 and R2 with different values of resistance are
connected in parallel. R1 allows 20% of total value of current to pass through it.

which among R1 and R2 offered lower resistance to the current flowing through

circuit and why?

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Answer 1

Answer:

Energy dissipated = PtorVI×tor =I

2

Rt Joules

Consider Ohm's law V=IR.

In this case the resistors are connected in series and hence, the total resistance is 4+2=6 ohms. In a series circuit, the current remains the same throughout the circuit and so we use the I

2

Rt Joules formula.

The total current in the circuit is calculated as I=V/R=6/6=1ampere.

Therefore, the power dissipated P across the 4 ohm resistor for 5 s

= 1

2

×4×5=20Joules

Hence, The heat dissipated by the 4 resistor in 5 s will be 20 J.

Answer 2

Answer:

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