Question

$\huge\fbox\red{h}\fbox\green{e}\fbox\blue{l}\fbox\orange{l}\fbox\purple{o}$
☆A wall 9.68 m long and 6.2 m high is covered with rectangular tiles of a size 44 cm by 20 cm. Find the total cost of the tiles at the rate of Rs. 18.50 per tile.
​

Answer 1

Answer:

Length =9.68m

Length =9.68mHeight=6.2m(breadth)

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles=

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles= Area of one tile

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles= Area of one tileArea of wall

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles= Area of one tileArea of wall

Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles= Area of one tileArea of wall Area of wall =9.68×6.2=60.016m

Area of wall =9.68×6.2=60.016m 2

=

= 0.088

= 0.08860.016

= 0.08860.016

= 0.08860.016

= 0.08860.016 =682

= 0.08860.016 =682Cost of 1 tile =18.50

= 0.08860.016 =682Cost of 1 tile =18.50Cost of 682 tiles =18.50×682

= 0.08860.016 =682Cost of 1 tile =18.50Cost of 682 tiles =18.50×682=12617

Step-by-step explanation:

Length =9.68m

Length =9.68mHeight=6.2m(breadth)

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m 2

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m 2

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m 2 Area of one tile=(0.44 *0.20)m^2=0.088m^2$$

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m 2 Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles=

Length =9.68mHeight=6.2m(breadth)Area of wall =9.68×6.2=60.016m 2 Area of one tile=(0.44 *0.20)m^2=0.088m^2$$No. of tiles= Area of onetile

Area of wall

=

= 0.088

= 0.08860.016

= 0.08860.016

= 0.08860.016

= 0.08860.016 =682

= 0.08860.016 =682Cost of 1 tile =18.50

= 0.08860.016 =682Cost of 1 tile =18.50Cost of 682 tiles =18.50×682

= 0.08860.016 =682Cost of 1 tile =18.50Cost of 682 tiles =18.50×682=12617

Answer 2

Given:

• Dimensions of the wall

→ Length : 9.68 m = 968cm

→ Breadth: 6.2m = 620cm

• Dimensions of the tiles

→ Length: 44cm

→ Breadth: 20cm

To find:

• Find the total cost of the tiles at the rate of Rs. 18.50 per tile.

Solution:

→ Now, let's first the the number of tiles fit in the wall

As we know that ,

${ \longrightarrow} \sf \: area \: of \: the \: wall \: = lenght \times \: breadth \\ \\ \\ { \longrightarrow} \sf \: area \: of \: the \: wall \: =968 \times 620 {cm}^{2} \: \: \: \: \\ \\ \\ { \longrightarrow} \sf \: area \: of \: the \: wall \: =600,160 {cm}^{2} \bigstar \: \: \:$

As we know that,

${ \longrightarrow} \sf \: area \: of \: the \:tile \: = \: 44cm \times 20cm \\ \\ \\ { \longrightarrow} \sf \: area \: of \: the \:tile \: = 880 {cm}^{2} \bigstar \: \: \: \: \: \:$

No of tiles which can be fit in the wall:

${ \longrightarrow} \sf \: No \: of \: tiles \: in \: the \: wall = \cancel\frac{600,160}{880} \\ \\ \\ { \longrightarrow} \sf \: No \: of \: tiles \: in \: the \: wall = 682 \bigstar \: \: \: \: \: \: \:$

→ Now, let's find the total cost

$\longrightarrow \sf \: total \: cost \: = 682 \times 18.50 \: rs \\ \\ \\ \orange{\longrightarrow \sf \: total \: cost = rs.12617 \bigstar} \: \: \: \: \: \: \:$

$\sf \: happy \: learning :D$