Question

$\huge \fbox \red{❥ Question}$


Find the value of “x” in the polynomial 2a2 + 2xa + 5a + 10 if (a + x) is one of its factors.​

Answer 1

Step-by-step explanation:

Answer:

2a²+2ax+5a+10

= 2a(a+x)+5(a+2)

So, x= 2

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Answer 2

$\huge{\underline{\underline{\huge{\bold{AnsweR \: :-}}}}}$

Say, f(a) = 2a² + 2xa + 5a + 10

Since, (a + x)is a factor of 2a² + 2xa + 5a +10, f(-x) = 0

So, f(-x) = 2x2 –2x2 –5x + 10 = 0

Or, -5x + 10 = 0

$\sf\large\color{blue}{Thus,\: x = 2}$