Question

$\huge (i)\dfrac{3 + \sqrt{2} }{3 - \sqrt{2} } = a + b \sqrt{2}$
Please solve the question...

No spam plz...

#BrainlyStar #EmergerModerator
@Somya2563​

Answer 1

$\huge{\mathcal {\purple {A}\green {n}\pink {s}\blue {w}\purple{e}\green {r}}}$

$\huge (i)\dfrac{3 + \sqrt{2} }{3 - \sqrt{2} } = a + b \sqrt{2}$

Do Rationalization,

(3+√2)(3+√2)/(3-√2)(3+√2)= a+b√2

9+6√2+2 / 9-2 = a+b√2

11+6√2 / 7 = a+b √2

11/7 + 6√2/7 = a+b√2

we can also write it as 11/7+6/7×√2 = a+b√2

So 11/7+6/7×√2 is in the form of a+b√2

So, we got the answer as

a=11/7 and b= 6/7

Answer : a=11/7 and b= 6/7

Answer 2

Answer:

(3+√2)(3+√2)/(3-√2)(3+√2)= a+b√2

9+6√2+2 / 9-2 = a+b√2

11+6√2 / 7 = a+b √2

11/7 + 6√2/7 = a+b√2

we can also write it as 11/7+6/7×√2 = a+b√2

So 11/7+6/7×√2 is in the form of a+b√2

Answer Is

a=11/7 and b= 6/7

Step-by-step explanation:

please mark me as a brain list