Question

$\huge \: if \: {x}^{2} + \frac{1}{ {x}^{2} } = 62$
$find \: \: \: the \: \: \: value \ \: \: : of \: - -$
$\huge \: x + \frac{1}{x}$



please solve it..
very urgent​

Answer 1

Answer:

x^2+1/x^2=62

(x+1/x)^2 =x^2+1/x^2+2

= (x+1/x)^2 = 62+2

= (x+1/x)^2 =64

= x+1/x = 8

Hope u understood the sum mere pyaari behen..!

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