Question

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The perimeter of a rectangle is 13 cm and width is 2. 3/4 cm
find its length​

Answer 1

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Given,

Breadth = $\sf{ \dfrac{2×4+3}{4}}$ $\sf{ = \dfrac{11}{4}cm}$

Let,the length of rectangle be x.

Now,

Perimeter = 2 × (length + breadth)

Perimeter = 2 $\sf{(x + \dfrac{11}{4})}$

Putting perimeter of rectangle = 13 cm

13 = 2 $\sf{(x + \dfrac{11}{4})}$

$\sf{ \dfrac{13}{2}=x + \dfrac{11}{4}}$

x + 11/4 = 13/2

x = 13/2 - 11/4

x = 13 × 2 - 11/4

x = 26 - 11/4

x = 15/4

x = 3 3/4

Therefore,

•°•Length of rectangle = x = 3 3/4 cm.