Math, asked by Anonymous, 3 months ago



\huge\mathcal\red{Hello \: friends } \\ \huge\mathcal\green{free \: points}
\huge{\red{\boxed{\purple{\boxed{\blue{\boxed{\green{\boxed{\orange{\boxed{\red{\boxed{\pink{G}\orange{O}\blue{O}\red{D} \: \green{M}\purple{O}\pink{R}\red{N}\blue{I}\green{N}\red{G}}}}}}}}}}}}}}
A brief information about two atoms X and Y is given:

X: Atomic number = 7, Mass number = 14

Y: Atomic number = 7, Mass number = 15

Which of the following is correct about
these two atoms?
(A) Electronic configuration of X is 2, 8,4
while that of Y is 2, 8, 5.
(B) Both X and Y contain 7 neutrons.
(C) X has 2 electron shells while Y has
3 electron shells.
(D) Both X and Y have 5 valence electrons.​​​

Answers

Answered by bswagatam04
1

Answer

(A) Electronic configuration is based on atomic number and not atomic mass.

So, electronic configuration of

X is 2,5 and Y is also 2,5.

(B) X contains 7 neutrons and Y contains 8 neutrons.

(C) Both X and Y have 2 shells as they have the same electronic configuration.

(D) We wrote the electronic configuration in option A, clearly both have valence electron 5.

So,Option D is True

Answered by IIRissingstarll
1

Answer:

(D) Both X and Y have 5 valence

electrons.

Similar questions