Question

$\huge{\mathcal{\underline{\green{QuEStiON}}}}$


Vijay had some bananas, and he divided them into two lots A and B. He sold the first lot at the rate of Rs. 2 for 3 bananas and the second lot at the rate of Rs. 1 per banana, and got a total of Rs. 400. If he had sold the first lot at the rate of Rs. 1 per banana, and the second lot at the rate of Rs. 4 for 5 bananas, his total collection would have been Rs. 460. Find the total number of bananas he had.

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Answer 1

Answer:

$\huge{\mathcal{\underline{\purple{AnsWER}}}}$

Let the no. of Bananas in Lots A be x and in Lots B be y .

Case 1 : $\frac{2}{3} x + y = 400 \: \: \: \: \: = > \: \: \: \: 2x + 3y = 1200$

Case 2 : $x + \frac{4}{5} y = 460 \: \: \: \: \: \: \: = > \: \: \: \: \: \: 5x + 4y = 2300$

X = 300

Y = 200

Total bananas = 500

Answer 2

Answer:

ANSWER

Let the no of banana A has=x

Let the no. of bananas B has=y

Am theg o twith first pricing=

3

x

(2)+y(1)=400

2x+3y=1200

2x+3y=1200−>eqn1

Am the got second pricing=x(1)+

5

y

(4)=460

5x+4y=2300

5x+4y=2300−>eqn2

Eqn1×5=10x+15y=6000

Eqn2×2=10x+8y=4600

Subtracting we get:7y=1400

y=200

Suby=200ineqn1

2x+3y=1200

2x+600=1200

2x=600

x=300

Total no of bananas=200+300=500

Step-by-step explanation:

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