Question

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show that ΔABC with vertics A(–2,0),B(0,2) and C(2,0) is similar to ΔDEF with vertics D(–4,0),F(4,0) and E(0,4).​

Answer 1

hope this helps u

ΔABC  and Δdef

we will prove by sss rule

a=(-2 ,0) b=(0,2) c=(2,0)

d=(-4,0) e=(0,4) f=(4,0)

a/d=b/e=c/f

-2,0/-4,0=0,2/0,4=2,0/4,0

0/0 get cancelled

-2/-4=2/4=2/4

1/2=1/2=1/2

1:2

since  sides are proportional by 1:2  If the corresponding sides of two triangles are proportional, then the two triangles are similar.

⇒ ΔABC ~is similar  ΔDEF