In the given figure, AB || CD. Find the value of x.
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on line DC at point H
180- 115 = DHQ = 65° ( STRAIGHT LINE ANGLE)
ANGLE PEF = PGH ( ANGLE ON SAME SIDE || LINE )
PGH + QGH = 180
180- 85 = 95 = QGH
IN TRIANGLE DHQ.
QGH + DHQ + X = 180 (ANGLE SUM IN TRIANGLE)
95+65 + X= 180
180-160 = X
20 = X .
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