In the given figure, AB || CD. Prove that BAE - ECD = AEC.
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Please find the answer below
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Step-by-step explanation:
Produce BA to touch EC. Let the point of intersection be F.
Then,
∠AFE=∠ECD
Also, ∠BAE=∠AFE+∠AEC
Therefore,
∠BAE=∠ECD+∠AEC
∠BAE−∠ECD=∠AEC
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