Question

$\huge\mathfrak\green{Hello\:Mate}$❤


Find all the zeroes of p(x) if it is completeley divisible by g(x).
$p(x) = 2 {x}^{4} + {x}^{3} - {14}^{2} + 5x + 6$
$g( x ) = {x}^{2} + 2x + k$

$\bold{@PhilophobiaXD}$✌​

Answer 1

${\huge {\mathfrak {Answer :-}}}$

✨ We have,

${} p(x) = 2 x^4 + x^3 - 14x^2 + 5x + 6$

⚠️ So, the steps are simple just you need to factorise it and you will get all the zeroes.

⚠️ Refer above ⬆️

⚠️ Ask if you have any doubts.

_________________

✨ HOPE THIS HELPS ✨

Answer 2

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

please refer to the attachment.

нσρє нєℓρѕ !❤️❤️