Question

$\Huge \mathfrak \pink{Hello \: Brainlymates}$
$\Huge\underline \blue{ Questions :-}$
✏️✏️Find the point A, where AB isthe diameter of a circle whose centre is (2,-3) and B is (1,4).


Answer with full explanation ✔️

Don't spam❌

don't copy from G.o.o.g.l.e ❌


$\Huge \mathfrak \pink{itzinnocentqueen711}$

​

Answer 1

Answer:

✳️Let the centre be as shown with center C (2,3)

✳️since AB is the diameter

✳️ centre C must be the midpoint of AB

✳️Let A(x,y)

✳️since C is the midpoint of AB

➡️x1=x,y1=y

➡️x2=1 , y2=4

➡️x co-ordinate⬇️

$x \: co - ordinate \: of \: c = \frac{x1 + x2}{2}$

$x \: co - ordinate \: of \: c \: = \frac{x + 1}{2} \\ 2 = \frac{x + 1}{2} \\ 2 \times 2 = \times + 1 \\ 4 = x + 1 \\ 4 - 1 = x \\ x = 3$

➡️y co-ordinate⬇️

$y \: co - ordinate \: of \: c \: = \frac{y1 + y2}{2}$

$y \: co - ordinate \: of \: c \: = \frac{y + 4}{2} \\ - 3 = \frac{y + 4}{2} \\ - 3 \times 2 = y + 4 \\ - 6 - 4 = y \\ y = - 10$

Step-by-step explanation:

hope you appreciate this ans

Answer 2

Answer:

$\huge \mathfrak \pink{refer \: to \: the \: attachment}$

$\huge \mathfrak \blue{hope \: it \: helps \: you}$