Math, asked by lavikaTomar, 5 months ago

The efficiency of carnot engine when source temperature
is T₁ and sink temperature is T2 will be
(a) T₁ - T₂/T₁
(b) T₂ - T₁/T₂ (c) T₁ - T₂/T₂
(d)T₁/T₂​

Answers

Answered by Anonymous
13

Answer:

b) T2-T1/T2

Step-by-step explanation:

the above is the answer

hope it helps u sis

Answered by shreyadwivedi488
4

Answer:

Efficiency of Carnot engine =η=

T1−T2/T1

where,

T1= source temperature

T2= sink temperature

so your answer is (A)

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