✏️✏️Find the relation between x and y such that the point (x,y) is a equidistant from the point (7,1) and (3,5)
need correct answer ✔️
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Step-by-step explanation:
Let P(x,y) be equidistant from the points A(7,1) and B(3,5).
AP=BP
AP 2 =BP 2
(x−7) 2 +(y−1) 2 =(x−3) 2 +(y−5) 2
x 2 −14x+49+y 2 −2y+1=x 2 −6x+9+y
2 −10y+25
x−y=2
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