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Find the linear combination of :
(i)963 and 657
(ii)506 and 1155
Answers
we need to find the HCF of 963 and 657 and express it as a linear combination of 963 and 657 by using Euclids division lemma,
963 = 657 x1 + 306
657= 306x2 + 45
306 =45 x 6 + 36
36 = 9x4 + 0
Hence HCF = 9
Now 9 = 45 - 36x1
= 45 - [306 -45 x6] x1
= 45 - [ 306 x 1 + 45x 6]
=45x 7 - 306 x1
=[ 657- 306 x2]x7 - 306x1
= 657x7 - 306x14 - 306x1
= 657 x7 - [963 - 657x1]x15
= 657 x7 - 963 x15 + 657 x15
= 657 x22 - 963 x 15
Hence obtained
second question : BYusing Euclis division lemma
a = bq + r ( 0lessthan or equal r less thsn b)
1155 = 506x2+ 143
506 = 143x3 + 77
143 = 77x1+ 66
66 = 11x6 +0
Therefore HCF = 11
Linear form:
506a + 1155b = 11
there are many solutions one of them
a= 16 and b = - 7
solution : 11 = 506 (16) + 1155( -7)
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Step-by-step explanation:
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