Question

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In the given figure ABCD is a quadrilateral-shaped field in Which diagonal BD is 36 cm, AL_ BD and CM_BD such that AL =19 m and CM=11 m. Find the area of the field.

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Answer 1

In the given figure,

BD = 36 cm, AL = 19 cm, CM = 11 cm.

Area of the field = Area of ΔABD + Area of ΔBCD

=> [(1/2) * BD * AL] * [(1/2) * BD * CM]

=> (1/2 * 36 * 19) * (1/2 * 36 * 11)

=> 540 cm²

Hence, the area of the field = 540 cm².

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Answer 2

Answer:

540 m²

Step-by-step explanation:

Area of field = area of two triangles Δ ABD and Δ BCD.

Area = 1/2 × AL × BD + 1/2 × CM × BD

⇒ 1/2 × BD ( AL + MC )

⇒ 1/2 × 36 × ( 19 + 11 )

⇒ 18 × 30

⇒ 540 m²