Question

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$\huge\mathfrak\red{✠Question}$
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1) A cycle was sold at a gain of 10%. Had it been sold for 260RS. more, the gain would have been 14%. Find the cost price of the cycle.​
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Answer 1

$\huge\mathfrak\red{✠Question}$

1) A cycle was sold at a gain of 10%. Had it been sold for 260RS. more, the gain would have been 14%. Find the cost price of the cycle.

$\huge\underbrace\purple{\dag AnsWeŘ\dag}$

Let x be the cost price of the cycle

Selling price when the cycle is sold at a gain of 14%

= 14x/100 = 114x/100

Selling price when cycle is sold at gain of 10%

= 114x/100 = 110x/100 = 260

= 4x/100 = 260

= x(260 * 100) / 4

= x(26000) / 4

= 6500

Therefore, the cost price of the cycle is Rs.6500

Answer 2

Answer:

$\huge\fcolorbox{blue}{pink}{☃αղsաҽɾ☃}$

$\huge\underline \bold{solution \: : - }$

$\bold{let \: the \: SP \:be \: x } \\ \ \\ \bold{gain \: = \: 10\%} \\ \\ \bold{gain \: = x + \: 10\% \: of \: x} \\ \\ \bold{gain = x + \frac{10}{100x} } \\ \\ \bold{gain = 100x + \frac{10x}{100} } \\ \\ \bold{gain = \frac{10x}{100} } \\ \\ \bold{}$

$\huge \bold{Now,}$

$\bold{gain = 14\%} \\ \\ \bold{gain =x + 14\% \: of \: x} \\ \\ \bold{gain = x + \frac{14}{100x} } \\ \\ \bold{gain = 100x + \frac{14x}{100} } \\ \\ \bold{gain = \frac{114x}{100} } \\ \\ \bold{ \frac{114x}{100} = \frac{110x}{100} + 260 } \\ \\ \bold{ \frac{114x}{1 00} - \frac{110x}{100} = 260} \\ \\ \bold{ \frac{4x}{100} = 260} \\ \\ \bold{ \frac{x}{25} = 260} \\ \\ \bold{x = 25 \times 260} \\ \\ \bold{x = 6500}$

$\bold{ \fbox \red {x =6500 }}$