Question

$\huge\mathfrak\red{ǫᴜᴇsᴛɪᴏɴ}$


the largest number which exactly divides 285 and 1245 leaving remainder 4 and 3


$\huge\mathfrak\red{ᴛʜᴀɴᴋ ʏᴏᴜ❥︎}$
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Answer 1

Answer:

answer is 138 is the answer

Answer 2

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To find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 5 respectively, we subtract 4 and 3 from 280 and 1245.

$280 - 4 = 276$

$1245 - 3 = 1242$

$276 = 2 \times 2 \times 3 \times 23$

$1242 = 2 \times 3 \times 3 \times 3 \times 23$

$HCF = 2 \times 3 \times 23 = 138$

∴ To find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 5 respectively, we subtract 4 and 3 from 280 and 1245 is 138.